i/p
array a holds 1 2 3 4
o/p of array b is 24 12 8 6
#include<stdio.h>
int main()
{
int n,i,j,a[100],b[100];
scanf("%d",&n);
for(i=0;i<n;i++)
{
scanf("%d",&a[i]);
}
for(i=0;i<n;i++)
{
b[i]=1;
for(j=0;j<n;j++)
{
if(i==j)
{
}
else
{
b[i]=b[i]*a[j];
}
}
}
for(i=0;i<n;i++)
printf("%d ",b[i]);
return 0;
}
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